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2x^2=127.69
We move all terms to the left:
2x^2-(127.69)=0
We add all the numbers together, and all the variables
2x^2-127.69=0
a = 2; b = 0; c = -127.69;
Δ = b2-4ac
Δ = 02-4·2·(-127.69)
Δ = 1021.52
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1021.52}}{2*2}=\frac{0-\sqrt{1021.52}}{4} =-\frac{\sqrt{}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1021.52}}{2*2}=\frac{0+\sqrt{1021.52}}{4} =\frac{\sqrt{}}{4} $
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